64^2/3x+2=128

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Solution for 64^2/3x+2=128 equation: 



64^2/3x+2=128

We move all terms to the left:

64^2/3x+2-(128)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

64^2/3x-126=0

We multiply all the terms by the denominator


-126*3x+64^2=0

We add all the numbers together, and all the variables

-126*3x+4096=0

Wy multiply elements

-378x+4096=0

We move all terms containing x to the left, all other terms to the right

-378x=-4096

x=-4096/-378

x=10+158/189

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